Question:

If a capacitor is charged by connecting it to a battery, then the ratio of work done by the battery and the energy stored in the capacitor is

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While charging a capacitor, \[ \boxed{ W_{\text{battery}}=CV^2, \qquad U=\frac12CV^2. } \] Half of the work done by the battery is stored in the capacitor and the remaining half is dissipated as heat.
Updated On: Jul 18, 2026
  • \(3:2\)
  • \(1:2\)
  • \(1:1\)
  • \(2:1\)
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The Correct Option is D

Solution and Explanation

Step 1: Find the work done by the battery. When a capacitor of capacitance \(C\) is charged to a potential difference \(V\), \[ Q=CV. \] The work done by the battery is \[ W=QV=CV^2. \]

Step 2:
Find the energy stored in the capacitor. The energy stored in the capacitor is \[ U = \frac12CV^2. \]

Step 3:
Find the required ratio. Therefore, \[ W:U = CV^2:\frac12CV^2 = 2:1. \] Hence, \[ \boxed{2:1}. \] Thus, \[ \boxed{(D)} \] is the correct answer.
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