If \(A=\begin{pmatrix}6 & 2\\7 & -5\end{pmatrix}\) and \(A-B=\begin{pmatrix}-2 & 1\\4 & -9\end{pmatrix}\) then \(B=\begin{pmatrix}8 & 1\\3 & 4\end{pmatrix}\)
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Matrices Tip: Always be careful with double negatives when subtracting matrices containing negative numbers. Writing out the intermediate step like $6 - (-2)$ prevents careless errors.
Concept:
Matrix addition and subtraction operate element-by-element, just like standard algebraic equations. If you are given matrix $A$ and the result of $A - B = C$, you can rearrange the equation algebraically to isolate $B$: $B = A - C$.
Step 1: Set up the algebraic relationship.
We are given:
$$A - B = \begin{pmatrix}-2 & 1\\ 4 & -9\end{pmatrix}$$
To find $B$, rearrange:
$$B = A - \begin{pmatrix}-2 & 1\\ 4 & -9\end{pmatrix}$$
Step 2: Substitute Matrix A into the equation.
$$B = \begin{pmatrix}6 & 2\\ 7 & -5\end{pmatrix} - \begin{pmatrix}-2 & 1\\ 4 & -9\end{pmatrix}$$