Question:

If \[ A= \begin{bmatrix} 2026 & 2025 & 2024 2025 & 2024 & 2023 2024 & 2023 & 2022 \end{bmatrix}, \] then \(\left|A^{2026}-A^{2025}\right|=\)

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If any matrix factor has determinant zero, then the determinant of the product is also zero.
Updated On: Jul 18, 2026
  • \(2026\)
  • \(2025\)
  • \(2024\)
  • \(0\)
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The Correct Option is D

Solution and Explanation

Observe that& nbsp;

\[ A^{2026}-A^{2025} = A^{2025}(A-I). \]

Taking determinants,

\[ \left|A^{2026}-A^{2025}\right| = |A^{2025}|\;|A-I|. \]

Now,

\[ A-I= \begin{bmatrix} 2025 & amp; 2025 & amp; 2024\\ 2025 & amp; 2023 & amp; 2023\\ 2024 & amp; 2023 & amp; 2021 \end{bmatrix}. \]

Since

\[ R_1-2R_2+R_3=0, \]

the rows are linearly dependent.

Hence,

\[ |A-I|=0. \]

Therefore,

\[ \boxed{\left|A^{2026}-A^{2025}\right|=0.} \]

Thus, the correct option is

\[ \boxed{(D)}. \]

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