Question:

If a, b, c are three distinct positive real numbers, the number of real roots of $ax²+2b|x|-c=0$ is

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If a, b, c are three distinct positive real numbers, the number of real roots of $ax+2b|x|-c=0$ is
Updated On: Apr 15, 2026
  • 4
  • 2
  • 0
  • None of these
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The Correct Option is B

Solution and Explanation

Step 1: Concept
Treat the equation as a quadratic in $|x|$.
Step 2: Analysis
$a|x|^2+2b|x|-c=0$. Using the quadratic formula: $|x| = \frac{-2b \pm \sqrt{4b^2 + 4ac}}{2a} = \frac{-b \pm \sqrt{b^2 + ac}}{a}$.
Step 3: Evaluation
Since $a, b, c>0$, $\sqrt{b^2 + ac}>b$. Thus, one value of $|x|$ is positive: $|x| = \frac{-b + \sqrt{b^2+ac}}{a}$. The other value is negative and rejected as $|x| \ge 0$.
Step 4: Conclusion
One positive value for $|x|$ yields two real values for $x$ (one positive, one negative).
Final Answer: (b)
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