Question:
If a, b,c are sides of a triangle and \(\begin{vmatrix} a^2&b^2&c^2\\(a+1)^2&(b+1)^2&(c+1)^2 \\ (a-1)^2&(b-1)^2&(c-1)^2\end{vmatrix}=0\) then \(\triangle ABC\) is
If a, b,c are sides of a triangle and \(\begin{vmatrix} a^2&b^2&c^2\\(a+1)^2&(b+1)^2&(c+1)^2 \\ (a-1)^2&(b-1)^2&(c-1)^2\end{vmatrix}=0\) then \(\triangle ABC\) is
Updated On: Oct 4, 2024
- equilateral
- right angled isoceles
- isoceles
- right angled
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The Correct Option is C
Solution and Explanation
The correct option is (C): isoceles
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