If \( a, b, c \) are \( p^{th}, q^{th} \) and \( r^{th} \) terms of a G.P, then the vectors \( \log a \,\hat{i} + \log b \,\hat{j} + \log c \,\hat{k} \) and \( (q-r)\hat{i} + (r-p)\hat{j} + (p-q)\hat{k} \) are
Show Hint
For G.P. problems involving logs, convert powers into linear form using logarithm properties.
Concept:
Vectors are perpendicular if their dot product is zero.
Step 1: Express terms of G.P.
Let G.P. be \( A, AR, AR^2, \dots \)
\[
a = AR^{p-1}, \quad b = AR^{q-1}, \quad c = AR^{r-1}
\]
Taking log:
\[
\log a = \log A + (p-1)\log R
\]
Similarly for \( b, c \)
Step 2: Form first vector:
\[
\vec{V_1} = (\log A + (p-1)\log R)\hat{i} + (\log A + (q-1)\log R)\hat{j} + (\log A + (r-1)\log R)\hat{k}
\]
Step 3: Dot product with second vector:
\[
\vec{V_1} \cdot \vec{V_2}
\]
Terms involving \( \log A \) cancel:
\[
(q-r) + (r-p) + (p-q) = 0
\]
Remaining terms also cancel $\Rightarrow$ Dot product = 0
Final Answer:
\[
\text{Vectors are perpendicular}
\]