Question:

If \(a,b,c\) are in arithmetic progression, then find the value of \[ \left| \begin{array}{ccc} x+2 & x+3 & x+2a\\ x+3 & x+4 & x+2b\\ x+4 & x+5 & x+2c\\ \end{array} \right|. \]

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Whenever entries in rows or columns follow an arithmetic progression, check for linear dependence. A determinant with linearly dependent rows or columns is always zero.
Updated On: Jun 6, 2026
  • \(2x\)
  • \(x\)
  • \(1\)
  • \(0\)
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The Correct Option is D

Solution and Explanation

Concept:
If three elements \(a,b,c\) are in arithmetic progression, then: \[ 2b=a+c \] A determinant becomes zero if its rows or columns become linearly dependent.

Step 1: Given determinant.
\[ \Delta= \left| \begin{array}{ccc} x+2 & x+3 & x+2a\\ x+3 & x+4 & x+2b\\ x+4 & x+5 & x+2c \end{array} \right| \]

Step 2: Use the A.P. condition.
\[ a,b,c \text{ are in A.P.} \] Therefore, \[ a+c=2b \]

Step 3: Observe the pattern in rows.

The first two columns increase regularly from row to row. The third column also becomes linearly related because \(a,b,c\) are in arithmetic progression.

Step 4: Linear dependence.

Since the columns are linearly dependent, the determinant must be zero. \[ \Delta=0 \] \[ \therefore \text{Correct Answer is (D)} \]
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