Concept:
If three elements \(a,b,c\) are in arithmetic progression, then:
\[
2b=a+c
\]
A determinant becomes zero if its rows or columns become linearly dependent.
Step 1: Given determinant.
\[
\Delta=
\left|
\begin{array}{ccc}
x+2 & x+3 & x+2a\\
x+3 & x+4 & x+2b\\
x+4 & x+5 & x+2c
\end{array}
\right|
\]
Step 2: Use the A.P. condition.
\[
a,b,c \text{ are in A.P.}
\]
Therefore,
\[
a+c=2b
\]
Step 3: Observe the pattern in rows.
The first two columns increase regularly from row to row. The third column also becomes linearly related because \(a,b,c\) are in arithmetic progression.
Step 4: Linear dependence.
Since the columns are linearly dependent, the determinant must be zero.
\[
\Delta=0
\]
\[
\therefore \text{Correct Answer is (D)}
\]