Question:

If \(A\), \(B\) and \(C\) represent work done, distance and electric charge respectively, then the physical quantity having the dimensions of \[ \frac{C^2}{AB} \] is

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Remember the standard dimensions: \[ [\varepsilon_0] = M^{-1}L^{-3}T^{4}I^{2}, \qquad [\mu_0] = MLT^{-2}I^{-2}. \] Questions on dimensions are often solved quickly by matching these standard forms.
Updated On: Jul 9, 2026
  • Permittivity
  • Permeability
  • Electric potential
  • Electric energy
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The Correct Option is A

Solution and Explanation

Concept: Write the dimensions of the given quantities: \[ [A]=[\text{Work}] =ML^2T^{-2} \] \[ [B]=[\text{Distance}] =L \] \[ [C]=[\text{Charge}] =IT \]

Step 1:
Find the dimensions of \(\dfrac{C^2}{AB}\). \[ \left[\frac{C^2}{AB}\right] = \frac{(IT)^2} {(ML^2T^{-2})(L)}. \] \[ = \frac{I^2T^2} {ML^3T^{-2}}. \] \[ = M^{-1}L^{-3}T^{4}I^{2}. \]

Step 2:
Compare with known dimensions. From Coulomb's law, \[ F=\frac{1}{4\pi\varepsilon_0} \frac{q_1q_2}{r^2}. \] Hence \[ [\varepsilon_0] = \frac{Q^2} {F\,r^2}. \] Substituting dimensions, \[ [\varepsilon_0] = \frac{(IT)^2} {(MLT^{-2})(L^2)}. \] \[ = M^{-1}L^{-3}T^{4}I^{2}. \] This matches the dimensions obtained above. \[ \therefore \frac{C^2}{AB} \text{ has the dimensions of permittivity.} \]

Step 3:
Write the final answer. \[ \boxed{\text{Permittivity}} \]
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