Concept:
Write the dimensions of the given quantities:
\[
[A]=[\text{Work}]
=ML^2T^{-2}
\]
\[
[B]=[\text{Distance}]
=L
\]
\[
[C]=[\text{Charge}]
=IT
\]
Step 1: Find the dimensions of \(\dfrac{C^2}{AB}\).
\[
\left[\frac{C^2}{AB}\right]
=
\frac{(IT)^2}
{(ML^2T^{-2})(L)}.
\]
\[
=
\frac{I^2T^2}
{ML^3T^{-2}}.
\]
\[
=
M^{-1}L^{-3}T^{4}I^{2}.
\]
Step 2: Compare with known dimensions.
From Coulomb's law,
\[
F=\frac{1}{4\pi\varepsilon_0}
\frac{q_1q_2}{r^2}.
\]
Hence
\[
[\varepsilon_0]
=
\frac{Q^2}
{F\,r^2}.
\]
Substituting dimensions,
\[
[\varepsilon_0]
=
\frac{(IT)^2}
{(MLT^{-2})(L^2)}.
\]
\[
=
M^{-1}L^{-3}T^{4}I^{2}.
\]
This matches the dimensions obtained above.
\[
\therefore
\frac{C^2}{AB}
\text{ has the dimensions of permittivity.}
\]
Step 3: Write the final answer.
\[
\boxed{\text{Permittivity}}
\]