Step 1: Understand the quantifiers
\(\exists\) means "there is at least one \(x\) in \(A\)" and \(\forall\) means "every \(x\) in \(A\)". We test each statement on \(x=1,2,3,4,5\).
Step 2: Check (A)
\(x+4\le9\) holds for \(x=5\) (and all others). So (A) is true.
Step 3: Check (B)
\(12-x=7\) gives \(x=5\), which is in \(A\). So (B) is true.
Step 4: Check (C)
The smallest value of \(x+3\) is \(1+3=4\ge4\), so it holds for all \(x\). So (C) is true.
Step 5: Check (D)
\(x+2<3\) means \(x<1\). No element of \(A\) is below \(1\). So (D) is false, and it is the statement that is not true.
Final Answer:
Only statement (D) fails, option (D).
\[ \boxed{\text{(D)}} \]