Question

If $2x^3-3y^2=7$, what is $\frac{dy}{dx}$ equal to $(y\ne 0)$:

• (A) $\frac{x^2}{2y}$
• (B) $\frac{x}{2y}$
• (C) $\frac{x^2}{y}$
• (D) None of the above

Answer 1

The Correct Option is C

Explanation:
Given,$2x^3-3y^2=7$Differentiating w.r.t. $x,$ we get$6x^2-6y\frac{dy}{dx}=0$$\Rightarrow x^2-y\frac{dy}{dx}=0$$\Rightarrow \frac{dy}{dx}=\frac{x^2}{y}$Hence, the correct option is (C).