Question:

If \( 1, \omega, \omega^2, \ldots, \omega^{n-1} \) are \( n \)th roots of unity, then the value of \( (9-\omega)(9-\omega^2)\cdots(9-\omega^{n-1}) \) is

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Always use $x^n - 1$ identity for roots of unity products.
Updated On: Apr 23, 2026
  • $\frac{9^n + 1}{8}$
  • $9^n - 1$
  • $\frac{9^n - 1}{8}$
  • $9^n + 1$
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The Correct Option is C

Solution and Explanation

Concept: Product of $(x - \omega^k)$ identity

Step 1:
\[ (x-1)(x-\omega)\cdots(x-\omega^{n-1}) = x^n - 1 \]

Step 2:
Put $x = 9$: \[ (9-1)(9-\omega)\cdots(9-\omega^{n-1}) = 9^n - 1 \]

Step 3:
Divide by $(9-1)=8$: \[ (9-\omega)(9-\omega^2)\cdots = \frac{9^n - 1}{8} \] Conclusion:
Answer = $\frac{9^n - 1}{8}$
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