Question

Identify ' Z' in the following reaction.

• A. \(\text{Ar}-\text{O}-\text{R}\)
• B.

  

• C.

  

• D.

  

Hint:

Phenol with an acid chloride in pyridine gives a phenyl ester, \(\text{RCOOAr}\).

Answer 1

The Correct Option is C

Step 1: Understanding the Concept
The figure shows Ar-OH reacting with an acyl chloride \(\text{Cl-CO-R}\) in the presence of pyridine, giving Z and HCl. This is acylation of phenol.

Step 2: Detailed Explanation
The OH oxygen attacks the carbonyl carbon and chloride leaves. The acyl group replaces the hydrogen of OH, forming an ester in which the aryl group is on the oxygen: \(\text{R-CO-O-Ar}\).
Pyridine takes up the HCl formed, which pushes the reaction forward.
The option that shows R-C(=O)-O-Ar is the third structure (C). The structure Ar-CO-OR (B) has the aryl group on carbon and so is an ester of an aromatic acid, and Ar-CO-R (D) is a ketone.

Final Answer:
Z is the phenyl ester \(\text{R-CO-O-Ar}\), option (C). \[ \boxed{\text{R-CO-O-Ar (C)}} \]