Question:

Identify the total number of complexes from following list having monodentate ligands in them
(a) Tetracyanonickelate (II) ion
(b) Potassium hexafluoroaluminate (III)
(c) Tetraamminecopper(II) ion
(d) Potassium trioxalatoaluminate (III)

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Cyanide, fluoride and ammine are monodentate; oxalate is bidentate.
Updated On: Oct 1, 2026
  • \(4\)
  • \(3\)
  • \(2\)
  • \(1\)
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept
A monodentate ligand binds the metal through one donor atom. Bidentate ligands bind through two.

Step 2: Detailed Explanation
(a) Tetracyanonickelate(II): CN\(^-\) is monodentate.
(b) Potassium hexafluoroaluminate(III): F\(^-\) is monodentate.
(c) Tetraamminecopper(II): NH\(_3\) is monodentate.
(d) Potassium trioxalatoaluminate(III): oxalate is bidentate, so this one is excluded.
Three complexes, (a), (b) and (c), have only monodentate ligands.

Final Answer:
Three of the listed complexes have monodentate ligands, option (B). \[ \boxed{3\ \text{(B)}} \]
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