Step 1: Analyze the first step of the reaction.
The reaction starts with \( C_2H_5I \) (ethyl iodide), which undergoes nucleophilic substitution in the presence of an alkali (\( \text{aq. KOH} \)) to form ethene (\( C_2H_4 \)) and an alcohol (ethanol). This indicates that the reagent [A] is \( \text{Br}_2/\text{CCl}_4 \), which is used for halogenation and prepares the compound for the next step of reaction.
Step 2: Analyze the second step of the reaction.
In the second step, the reaction of ethene (\( C_2H_4 \)) with \( \text{NaNH}_2 \) (sodium amide) results in the formation of an alkyne. The alkyne then undergoes elimination in the presence of a red-hot metal tube (such as red-hot Fe) to form benzene (\( C_6H_6 \)).
Step 3: Confirm the reagents and conditions.
The reagents used are consistent with the Finkelstein reaction and elimination mechanisms:
- \( \text{Br}_2 / \text{CCl}_4 \) is used for halogenation.
- \( \text{aq. KOH} \) is used to prepare ethene.
- \( \text{NaNH}_2 \) is used to form the alkyne intermediate.
- \( \text{Red hot Fe tube} \) is used to complete the reaction and form the final product, benzene.
Step 4: Conclusion.
Thus, the correct reagents for the given reaction are as described in option (A). The correct answer is option (A).