To solve the problem, we need to understand the oxidation process of alcohols, focusing on primary, secondary, and tertiary alcohols:
Primary Alcohols: These are oxidized to aldehydes, which can be further oxidized to carboxylic acids without altering the number of carbon atoms. This statement is true.
Secondary Alcohols: These are oxidized to ketones. However, for further oxidation to carboxylic acids, the carbon chain is typically broken, resulting in acids with a smaller number of carbon atoms. Thus, secondary alcohols do not form acids with the same number of C-atoms through oxidation. Based on this, the following point is incorrect:
Secondary alcohols are very easily oxidised to ketones, which are oxidised to acids with the same number of C-atoms.
Tertiary Alcohols: These are resistant to oxidation; under strong conditions, they might break into smaller fragments, resulting in carboxylic acids with fewer carbon atoms. This aligns with the true statement regarding secondary and tertiary alcohols forming acids with fewer C-atoms.
Thus, the incorrect statement among the provided options is:
Secondary alcohols are very easily oxidised to ketones, which are oxidised to acids with the same number of C-atoms.
Compounds A and B, having the same molecular formula \( C_4H_8O \), react separately with \( CH_3MgBr \), followed by reaction with dil. HCl to form compounds X and Y respectively. Compound Y undergoes acidic dehydration in the presence of Conc. \( H_2SO_4 \) much more readily than X. Compound Y also reacts with Lucas reagent, much more readily than X, with the appearance of turbidity. Identify X and Y.
The following reaction takes place: 