Question:
Identify the reagent \(R\) used in following reaction.
\(\text{Ketone} \xrightarrow{R} \text{semi carbazone}\)
Identify the reagent \(R\) used in following reaction.
\(\text{Ketone} \xrightarrow{R} \text{semi carbazone}\)
\(\text{Ketone} \xrightarrow{R} \text{semi carbazone}\)
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Ketone derivatives: oxime (NH$_2$OH), hydrazone (NH$_2$NH$_2$), semicarbazone (NH$_2$NHCONH$_2$).
Updated On: Apr 26, 2026
- \(\text{NH}_2\text{OH}\)
- \(\text{NH}_2\text{NHCONH}_2\)
- \(\text{NH}_2\text{NHC}_6\text{H}_5\)
- \(\text{NH}_2 - \text{NH}_2\)
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The Correct Option is B
Solution and Explanation
Concept:
Carbonyl compounds react with derivatives of ammonia to form characteristic derivatives. Step 1: Identify reaction type. Ketones react with semicarbazide to form semicarbazone: \[ \text{R}_2\text{C=O} + \text{NH}_2\text{NHCONH}_2 \rightarrow \text{R}_2\text{C=NNHCONH}_2 \]
Step 2: Identify reagent. \[ \text{Semicarbazide} = \text{NH}_2\text{NHCONH}_2 \]
Step 3: Conclusion. Reagent required is semicarbazide.
Carbonyl compounds react with derivatives of ammonia to form characteristic derivatives. Step 1: Identify reaction type. Ketones react with semicarbazide to form semicarbazone: \[ \text{R}_2\text{C=O} + \text{NH}_2\text{NHCONH}_2 \rightarrow \text{R}_2\text{C=NNHCONH}_2 \]
Step 2: Identify reagent. \[ \text{Semicarbazide} = \text{NH}_2\text{NHCONH}_2 \]
Step 3: Conclusion. Reagent required is semicarbazide.
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