Identify the reaction for which, at equilibrium, a change in the volume of the closed reaction vessel at a constant temperature will not affect the extent of the reaction
At equilibrium, the effect of a change in volume is determined by the number of gaseous
moles on either side of the reaction.
If the total number of gaseous moles changes during the reaction, a change in volume
will shift the equilibrium to favor the side with more or fewer moles of gas (as per Le
Chatelier’s principle).
If the total number of gaseous moles remains the same, a change in volume will not
affect the extent of the reaction.
Let’s analyze each option:
(A) CaCO3(s) ⇌ CaO(s) + CO2(g) : This reaction involves a change in the number of moles
of gas (0 → 1). Hence, a change in volume will affect the equilibrium.
(B) H2(g) + I2(g) ⇌ 2HI(g) : The number of gaseous moles on both sides of the reaction is
the same (2 → 2). Thus, a change in volume will not affect the equilibrium.
(C) 2NO2(g) ⇌ N2O4(g) : This reaction involves a change in the number of gaseous moles
(2 → 1). Hence, a change in volume will affect the equilibrium.
(D) CO2(s) ⇌ CO2(g) : This reaction involves a change from a solid to a gas (0 → 1).
Hence, a change in volume will affect the equilibrium.