Question

Identify the products formed when benzenediazonium chloride reacts with CuCl / HCl
\(\text{C}_{6}\text{H}_{5}\text{N}_{2}^{+}\text{Cl}^{-}+\text{CuCl}\rightarrow\)

• A. \(\text{C}_{6}\text{H}_{5}\text{Cl}+\text{N}_{2}\)
• B. \(\text{C}_{6}\text{H}_{5}\text{Br}+\text{N}_{2}\)
• C. \(\text{C}_{6}\text{H}_{6}+\text{N}_{2}\)
• D. \(\text{C}_{6}\text{H}_{5}\text{OH}\)

Hint:

This is the Sandmeyer reaction, which replaces the diazonium group by chlorine.

Answer 1

The Correct Option is A

Step 1: Understanding the Concept
Treating a diazonium salt with CuCl/HCl is the Sandmeyer reaction, in which the \(-\text{N}_2^{+}\) group is replaced by \(-\text{Cl}\).

Step 2: Write the reaction
\(\text{C}_6\text{H}_5\text{N}_2^{+}\text{Cl}^{-}\xrightarrow{\text{CuCl/HCl}}\text{C}_6\text{H}_5\text{Cl}+\text{N}_2\)

Step 3: Compare the options
Chlorobenzene and nitrogen match the first option.

Final Answer:
Chlorobenzene and nitrogen gas are formed. \[ \boxed{\text{(A) }\text{C}_{6}\text{H}_{5}\text{Cl}+\text{N}_{2}} \]