Question:
Identify the product when sulfur dioxide reacts with sodium hydroxide solution.
Identify the product when sulfur dioxide reacts with sodium hydroxide solution.
Show Hint
Sulfur dioxide is an acidic oxide, so a base neutralises it to give a salt in which sulfur stays in the +4 state.
Updated On: Nov 12, 2026
- Sodium sulfite
- Sodium sulfate
- Sodium hydrogen sulfate
- Sodium hydrogen sulfite
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
\(\text{SO}_2\) is an acidic oxide. With an alkali it forms a salt and water, just as an acid would.
Step 2: Write the reaction
With sodium hydroxide solution:
\(\text{SO}_2 + 2\text{NaOH} \rightarrow \text{Na}_2\text{SO}_3 + \text{H}_2\text{O}\)
Step 3: Oxidation state of sulfur
Sulfur is \(+4\) in \(\text{SO}_2\) and stays \(+4\) in the product. A sulfate would need sulfur in the \(+6\) state, which cannot form here.
Step 4: Choose the option
The hydrogen sulfite \(\text{NaHSO}_3\) appears only when \(\text{SO}_2\) is in excess. With NaOH the normal salt, sodium sulfite, is formed.
Final Answer:
The product is sodium sulfite. \[ \boxed{\text{(A) }\text{Sodium sulfite}} \]
\(\text{SO}_2\) is an acidic oxide. With an alkali it forms a salt and water, just as an acid would.
Step 2: Write the reaction
With sodium hydroxide solution:
\(\text{SO}_2 + 2\text{NaOH} \rightarrow \text{Na}_2\text{SO}_3 + \text{H}_2\text{O}\)
Step 3: Oxidation state of sulfur
Sulfur is \(+4\) in \(\text{SO}_2\) and stays \(+4\) in the product. A sulfate would need sulfur in the \(+6\) state, which cannot form here.
Step 4: Choose the option
The hydrogen sulfite \(\text{NaHSO}_3\) appears only when \(\text{SO}_2\) is in excess. With NaOH the normal salt, sodium sulfite, is formed.
Final Answer:
The product is sodium sulfite. \[ \boxed{\text{(A) }\text{Sodium sulfite}} \]
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