Question:
Identify the product when glucose reacts with bromine water.
Identify the product when glucose reacts with bromine water.
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Bromine water oxidises only the aldehyde group of glucose to a carboxylic acid.
Updated On: Oct 1, 2026
- Saccharic acid
- Cyanohydrin
- Gluconic acid
- Nucleic acid
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Verified By Collegedunia
The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
Glucose has an aldehyde group at C1 and a primary alcohol at C6. Bromine water is a mild oxidising agent.
Step 2: Reaction
Bromine water oxidises only the aldehyde group to a carboxylic acid group, leaving the rest of the chain unchanged:
\[ \text{CHO-(CHOH)}_4\text{-CH}_2\text{OH}\xrightarrow{\text{Br}_2/\text{H}_2\text{O}}\text{COOH-(CHOH)}_4\text{-CH}_2\text{OH} \]
The product is gluconic acid.
Step 3: Compare the others
Saccharic acid forms with strong oxidation by nitric acid, where both end groups become COOH. Cyanohydrin forms with HCN. Nucleic acids are polymers and have nothing to do with this reaction.
Final Answer:
Bromine water turns the CHO group of glucose into COOH, giving gluconic acid, option (C). \[ \boxed{\text{Gluconic acid}} \]
Glucose has an aldehyde group at C1 and a primary alcohol at C6. Bromine water is a mild oxidising agent.
Step 2: Reaction
Bromine water oxidises only the aldehyde group to a carboxylic acid group, leaving the rest of the chain unchanged:
\[ \text{CHO-(CHOH)}_4\text{-CH}_2\text{OH}\xrightarrow{\text{Br}_2/\text{H}_2\text{O}}\text{COOH-(CHOH)}_4\text{-CH}_2\text{OH} \]
The product is gluconic acid.
Step 3: Compare the others
Saccharic acid forms with strong oxidation by nitric acid, where both end groups become COOH. Cyanohydrin forms with HCN. Nucleic acids are polymers and have nothing to do with this reaction.
Final Answer:
Bromine water turns the CHO group of glucose into COOH, giving gluconic acid, option (C). \[ \boxed{\text{Gluconic acid}} \]
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