Question:
Identify the product obtained when phenol reacts with bromine in presence of \(\text{CS}_{2}\)
Identify the product obtained when phenol reacts with bromine in presence of \(\text{CS}_{2}\)
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In a non-polar solvent like CS2 only monobromination occurs at the ortho and para positions.
Updated On: Nov 12, 2026
- P-Bromophenol
- Mixture of O-Bromophenol and P-Bromophenol
- 2, 4, 6-tribromophenol
- m-Bromophenol
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
In bromine water, phenol gives 2,4,6-tribromophenol because the ring is strongly activated and phenol ionises.
Step 2: Effect of the solvent
In \(\text{CS}_2\), a non-polar solvent, phenol does not ionise and bromine is only weakly polarised.
So substitution stops after a single bromine atom.
Step 3: Product
The \(-\text{OH}\) group directs to the ortho and para positions.
The products are o-bromophenol (minor) and p-bromophenol (major).
Final Answer:
The product is a mixture of o-bromophenol and p-bromophenol. \[ \boxed{\text{(B) }\text{Mixture of O-Bromophenol and P-Bromophenol}} \]
In bromine water, phenol gives 2,4,6-tribromophenol because the ring is strongly activated and phenol ionises.
Step 2: Effect of the solvent
In \(\text{CS}_2\), a non-polar solvent, phenol does not ionise and bromine is only weakly polarised.
So substitution stops after a single bromine atom.
Step 3: Product
The \(-\text{OH}\) group directs to the ortho and para positions.
The products are o-bromophenol (minor) and p-bromophenol (major).
Final Answer:
The product is a mixture of o-bromophenol and p-bromophenol. \[ \boxed{\text{(B) }\text{Mixture of O-Bromophenol and P-Bromophenol}} \]
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