Question:
Identify the product obtained when phenol is treated with bromine water.
Identify the product obtained when phenol is treated with bromine water.
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Phenol gives tribromination with bromine water due to strong activating effect of –OH group.
Updated On: Feb 11, 2026
- p–Bromophenol
- m–Bromophenol
- 2,4,6–Tribromophenol
- o–Bromophenol
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The Correct Option is C
Solution and Explanation
Step 1: Understand the activating nature of phenol.
Phenol has a strongly activating –OH group which increases electron density at ortho and para positions.
Step 2: Reaction with bromine water.
Bromine water is a strong brominating agent. Phenol reacts readily without a catalyst.
Step 3: Formation of product.
Substitution occurs at all three activated positions (2, 4, and 6), forming a white precipitate.
Step 4: Conclusion.
The product formed is 2,4,6–tribromophenol.
Phenol has a strongly activating –OH group which increases electron density at ortho and para positions.
Step 2: Reaction with bromine water.
Bromine water is a strong brominating agent. Phenol reacts readily without a catalyst.
Step 3: Formation of product.
Substitution occurs at all three activated positions (2, 4, and 6), forming a white precipitate.
Step 4: Conclusion.
The product formed is 2,4,6–tribromophenol.
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