Question:
Identify the product formed when glucose is treated with dil. \(\text{HNO}_{3}\).
Identify the product formed when glucose is treated with dil. \(\text{HNO}_{3}\).
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Nitric acid oxidises both ends of the glucose chain.
Updated On: Nov 12, 2026
- Saccharic acid
- Oxalic acid
- Gluconic acid
- Malonic acid
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The Correct Option is A
Solution and Explanation
Step 1: Understanding the Concept
Nitric acid is a strong oxidising agent. It oxidises both the -CHO group at C-1 and the primary -CH2OH group at C-6 of glucose.
Step 2: Product
Both ends become -COOH, giving the dicarboxylic acid called saccharic acid (glucaric acid).
Step 3: Compare
Mild oxidation with bromine water oxidises only the -CHO group and gives gluconic acid.
Final Answer:
Glucose with dilute nitric acid gives saccharic acid. \[ \boxed{\text{(A) }\text{Saccharic acid}} \]
Nitric acid is a strong oxidising agent. It oxidises both the -CHO group at C-1 and the primary -CH2OH group at C-6 of glucose.
Step 2: Product
Both ends become -COOH, giving the dicarboxylic acid called saccharic acid (glucaric acid).
Step 3: Compare
Mild oxidation with bromine water oxidises only the -CHO group and gives gluconic acid.
Final Answer:
Glucose with dilute nitric acid gives saccharic acid. \[ \boxed{\text{(A) }\text{Saccharic acid}} \]
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