Step 1: Understanding the Question:
The question asks for the principal product formed during the chemical reaction of ethylbenzene with nitric acid under typical oxidative conditions.
Step 2: Key Formula or Approach:
Alkyl side chains attached to aromatic benzene rings are highly susceptible to strong oxidative cleavage at the benzylic position when heated with robust mineral oxidants such as concentrated nitric acid ($\text{HNO}_3$) or potassium permanganate ($\text{KMnO}_4$). Regardless of the length of the alkyl side chain, the entire chain is oxidized down to a single carboxylic acid group attached directly to the ring.
Step 3: Detailed Explanation:
Let's analyze the structural behavior of ethylbenzene ($\text{C}_6\text{H}_5\text{-CH}_2\text{-CH}_3$):
The carbon atom directly bound to the aromatic ring is the benzylic carbon and holds two benzylic hydrogens.
When treated with hot, concentrated nitric acid ($\text{HNO}_3$), it acts as a strong oxidizing agent rather than a nitrating mixture (since sulfuric acid is absent here).
The oxidative cleavage cleaves the C-C bond of the ethyl group, converting the benzylic carbon into a carboxyl group ($-\text{COOH}$), while the terminal methyl carbon escapes as carbon dioxide ($\text{CO}_2$).
The total transformation can be written as:
$$\text{C}_6\text{H}_5\text{-CH}_2\text{-CH}_3 \xrightarrow{\text{HNO}_3,\, \Delta} \text{C}_6\text{H}_5\text{-COOH}$$
The final aromatic product is benzoic acid, which matches option (D).
Step 4: Final Answer:
The product formed when ethylbenzene reacts with nitric acid under these conditions is Benzoic acid, which corresponds to option (D).