Question:
Identify the product formed when ethyl alcohol reacts with \(\text{H}_{2}\text{SO}_{4}\) at 443 K.
Identify the product formed when ethyl alcohol reacts with \(\text{H}_{2}\text{SO}_{4}\) at 443 K.
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The product depends on temperature: 443 K favours elimination, not ether formation.
Updated On: Nov 12, 2026
- Ethoxy ethane
- Ethene
- Dimethyl ether
- Ethyl hydrogen sulphate
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
Ethanol reacts with concentrated \(\text{H}_2\text{SO}_4\) in different ways depending on the temperature.
Step 2: Temperature effect
At 443 K with excess acid, intramolecular dehydration occurs and ethene is formed:
\(\text{C}_2\text{H}_5\text{OH}\rightarrow\text{CH}_2=\text{CH}_2+\text{H}_2\text{O}\).
At 413 K with excess alcohol, diethyl ether forms, and at low temperature ethyl hydrogen sulphate forms.
Step 3: Conclusion
At 443 K the product is ethene.
Final Answer:
At 443 K ethanol gives ethene. \[ \boxed{\text{(B) }\text{Ethene}} \]
Ethanol reacts with concentrated \(\text{H}_2\text{SO}_4\) in different ways depending on the temperature.
Step 2: Temperature effect
At 443 K with excess acid, intramolecular dehydration occurs and ethene is formed:
\(\text{C}_2\text{H}_5\text{OH}\rightarrow\text{CH}_2=\text{CH}_2+\text{H}_2\text{O}\).
At 413 K with excess alcohol, diethyl ether forms, and at low temperature ethyl hydrogen sulphate forms.
Step 3: Conclusion
At 443 K the product is ethene.
Final Answer:
At 443 K ethanol gives ethene. \[ \boxed{\text{(B) }\text{Ethene}} \]
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