Question:
Identify the product formed in the following reaction.
\[
\mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CHO} \xrightarrow[\text { ii) } \mathrm{H}_3 \mathrm{O}^{+}]{\text {i) } \mathrm{LiAlH}_4} \text { Product }
\]
Identify the product formed in the following reaction.
\[ \mathrm{CH}_3-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_2-\mathrm{CHO} \xrightarrow[\text { ii) } \mathrm{H}_3 \mathrm{O}^{+}]{\text {i) } \mathrm{LiAlH}_4} \text { Product } \]Show Hint
LiAlH4 reduces the aldehyde group but does not touch an isolated C=C bond.
Updated On: Nov 13, 2026
\(\mathrm{CH}_{3}-(\mathrm{CH}_{2})_{3}-\mathrm{CH}_{2}-\mathrm{OH}\)
\(\mathrm{CH}_{3}-\mathrm{CH}_{2}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{OH}\)
\(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{OH}\)
\(\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{OH}\)
Show Solution
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
\(\text{LiAlH}_4\) is a strong hydride donor that reduces \(-\text{CHO}\) to a primary alcohol \(-\text{CH}_2\text{OH}\). It does not reduce isolated carbon-carbon double bonds.
Step 2: Apply
\(\text{CH}_3\text{CH}=\text{CH}\text{CH}_2\text{CHO}\rightarrow\text{CH}_3\text{CH}=\text{CH}\text{CH}_2\text{CH}_2\text{OH}\).
Step 3: Compare the options
The double bond stays and the aldehyde becomes \(-\text{CH}_2\text{OH}\). Option (C).
Final Answer:
The product is pent-3-en-1-ol. \[ \boxed{\text{(C) }\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{OH}} \]
\(\text{LiAlH}_4\) is a strong hydride donor that reduces \(-\text{CHO}\) to a primary alcohol \(-\text{CH}_2\text{OH}\). It does not reduce isolated carbon-carbon double bonds.
Step 2: Apply
\(\text{CH}_3\text{CH}=\text{CH}\text{CH}_2\text{CHO}\rightarrow\text{CH}_3\text{CH}=\text{CH}\text{CH}_2\text{CH}_2\text{OH}\).
Step 3: Compare the options
The double bond stays and the aldehyde becomes \(-\text{CH}_2\text{OH}\). Option (C).
Final Answer:
The product is pent-3-en-1-ol. \[ \boxed{\text{(C) }\mathrm{CH}_{3}-\mathrm{CH}=\mathrm{CH}-\mathrm{CH}_{2}-\mathrm{CH}_{2}-\mathrm{OH}} \]
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