Question:
Identify the product 'B' in the following sequence of reactions.
Ethanenitrile \( \xrightarrow{\text{SnCl}_2, \text{HCl}} \) A \( \xrightarrow{\text{H}_3\text{O}^+} \) B + NH\(_4\)Cl}
Identify the product 'B' in the following sequence of reactions.
Ethanenitrile \( \xrightarrow{\text{SnCl}_2, \text{HCl}} \) A \( \xrightarrow{\text{H}_3\text{O}^+} \) B + NH\(_4\)Cl}
Ethanenitrile \( \xrightarrow{\text{SnCl}_2, \text{HCl}} \) A \( \xrightarrow{\text{H}_3\text{O}^+} \) B + NH\(_4\)Cl}
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Stephen Reaction: Nitrile $\rightarrow$ Imine $\rightarrow$ Aldehyde.
Updated On: Apr 30, 2026
- Ethylamine
- Ethanamide
- Ethanol
- Ethanal
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The Correct Option is D
Solution and Explanation
Step 1: Reaction Name
This sequence ($SnCl_2/HCl$ followed by hydrolysis) is the **Stephen Reaction**.
Step 2: Identify Intermediate A
Ethanenitrile ($CH_3CN$) is reduced by $SnCl_2/HCl$ to form an imine hydrochloride: $CH_3CH=NH \cdot HCl$ (Intermediate A).
Step 3: Hydrolysis
Hydrolysis of the imine intermediate ($A$) yields the corresponding aldehyde. $CH_3CH=NH \xrightarrow{H_3O^+} CH_3CHO + NH_4^+$.
Step 4: Conclusion
Product B is Ethanal (Acetaldehyde).
Final Answer:(D)
This sequence ($SnCl_2/HCl$ followed by hydrolysis) is the **Stephen Reaction**.
Step 2: Identify Intermediate A
Ethanenitrile ($CH_3CN$) is reduced by $SnCl_2/HCl$ to form an imine hydrochloride: $CH_3CH=NH \cdot HCl$ (Intermediate A).
Step 3: Hydrolysis
Hydrolysis of the imine intermediate ($A$) yields the corresponding aldehyde. $CH_3CH=NH \xrightarrow{H_3O^+} CH_3CHO + NH_4^+$.
Step 4: Conclusion
Product B is Ethanal (Acetaldehyde).
Final Answer:(D)
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