Question:

Identify the polymer obtained from 1,3-butadiene and acrylonitrile.

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Polymer Tip: Remember the names by their components: Buna-S uses Styrene, while Buna-N uses acryloNitrile.
Updated On: Apr 23, 2026
  • Polyacrylamide
  • Buna N
  • Glyptal
  • Perspex
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The Correct Option is B

Solution and Explanation

Concept: Chemistry (Polymers) - Addition Polymers and Copolymers.

Step 1:
Identify the reacting monomers. The given monomers are 1,3-butadiene ($CH_2=CH-CH=CH_2$) and acrylonitrile ($CH_2=CH-CN$).

Step 2:
Determine the type of polymerization. Since both monomers contain double bonds, they undergo an addition polymerization reaction. Because there are two different monomers involved, it is specifically a copolymerization.

Step 3:
Analyze the reaction mechanism. The reaction typically proceeds via a free-radical mechanism in the presence of a peroxide catalyst. The double bonds in 1,3-butadiene open up to form a continuous carbon chain, shifting a double bond to the central carbons, while the double bond in acrylonitrile also opens to link with the butadiene units.

Step 4:
Formulate the polymer structure. The repeating unit formed by linking 1,3-butadiene and acrylonitrile is $-[-CH_2-CH=CH-CH_2-CH_2-CH(CN)-]_n-$.

Step 5:
Identify the common name of the polymer. The synthetic rubber formed from Butadiene and acryloNitrile is commercially known as Buna-N (or Nitrile rubber). Here, 'Bu' stands for butadiene, 'na' for the sodium catalyst originally used in similar reactions, and 'N' for acrylonitrile. $$ \therefore \text{The polymer obtained is Buna N.} $$
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