Step 1: Determine the charge on the complex ion.
Since there are three \(\text{K}^+\) ions, the charge on the complex ion is \(-3\). Step 2: Assign charges to ligands.
Each oxalate ion \((\text{C}_2\text{O}_4)^{2-}\) has a charge of \(-2\).
Total charge from ligands \(= 3 \times (-2) = -6\). Step 3: Calculate oxidation state of chromium.
Let oxidation state of Cr be \(x\):
\[
x - 6 = -3 \Rightarrow x = +3
\]
Step 4: Conclusion.
The oxidation state of chromium is \(+3\).