Question

Identify the monomer units used in the preparation of Nylon-6,6.

• A. Adipic acid and Hexamethylenediamine
• B. Terephthalic acid and Ethylene glycol
• C. Caprolactam
• D. Styrene

Hint:

Nylon naming rule: Nylon-\(x,y\) indicates the number of carbon atoms in the diamine (\(x\)) and the dicarboxylic acid (\(y\)). For Nylon-6,6 both monomers contain 6 carbon atoms.

Answer 1

The Correct Option is A

Concept: Nylon-6,6 is a condensation polymer formed by the reaction between a dicarboxylic acid and a diamine. During polymerization, molecules join together with the elimination of small molecules such as water.

Step 1: Identify the reacting monomers. The two monomers involved are: \[ \text{Adipic acid } (HOOC-(CH_2)_4-COOH) \] and \[ \text{Hexamethylenediamine } (H_2N-(CH_2)_6-NH_2) \]

Step 2: Formation of Nylon-6,6. These two monomers undergo condensation polymerization forming amide linkages \((-CONH-)\), producing the polymer Nylon-6,6. \[ \text{Adipic acid} + \text{Hexamethylenediamine} \rightarrow \text{Nylon-6,6} + H_2O \] Thus, the monomers used are: \[ \boxed{\text{Adipic acid and Hexamethylenediamine}} \]