Question:

Identify the major product formed when 2-Methylhexan-3-ol is heated with concentrated sulphuric acid.

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Acid-catalysed dehydration follows Saytzeff's rule and gives the more substituted alkene.
Updated On: Nov 13, 2026
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The Correct Option is A

Solution and Explanation

Step 1: Understanding the Concept
Heating an alcohol with concentrated \(\text{H}_2\text{SO}_4\) causes dehydration. The major product is the more substituted (more stable) alkene, by Saytzeff's rule.

Step 2: Structure of the Alcohol
2-Methylhexan-3-ol is \((\text{CH}_3)_2\text{CH}-\text{CH(OH)}-\text{CH}_2\text{CH}_2\text{CH}_3\).

Step 3: Possible Alkenes
Removing H from C-2 gives \((\text{CH}_3)_2\text{C}=\text{CH}-\text{CH}_2\text{CH}_2\text{CH}_3\), a trisubstituted alkene. Removing H from C-4 gives a disubstituted alkene.

Step 4: Match the Image
Option (A) shows the trisubstituted alkene 2-methylhex-2-ene, which is the major product.

Final Answer:
The major product is 2-methylhex-2-ene. \[ \boxed{\text{(A) }\text{2-Methylhex-2-ene (trisubstituted alkene)}} \]
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