Question:
Identify the major product formed when 2-chlorobutane is boiled with concentrated alcoholic \(\text{KOH}\) .
Identify the major product formed when 2-chlorobutane is boiled with concentrated alcoholic \(\text{KOH}\) .
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Saytzeff rule: More substituted alkene is major product.
Updated On: May 4, 2026
- Butan-2-ol
- Butan-1-ol
- But-1-ene
- But-2-ene
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The Correct Option is D
Solution and Explanation
Concept:
Alcoholic KOH favors elimination (E2) reaction → alkene formation.
Step 1: Reaction type. \[ \text{Alkyl halide} \xrightarrow{\text{alc. KOH}} \text{Alkene} \]
Step 2: Apply Saytzeff rule. More substituted alkene is the major product.
• But-2-ene (more stable)
• But-1-ene (less stable)
Step 3: Conclusion. \[ \text{Major product = But-2-ene} \]
Alcoholic KOH favors elimination (E2) reaction → alkene formation.
Step 1: Reaction type. \[ \text{Alkyl halide} \xrightarrow{\text{alc. KOH}} \text{Alkene} \]
Step 2: Apply Saytzeff rule. More substituted alkene is the major product.
• But-2-ene (more stable)
• But-1-ene (less stable)
Step 3: Conclusion. \[ \text{Major product = But-2-ene} \]
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