Step 1: Understanding the Concept
A half-filled 4f subshell holds \(4f^{7}\) and a completely filled one holds \(4f^{14}\). Write the configuration of each ion and count the 4f electrons.
Step 2: Calculation
Tb is \([\text{Xe}]4f^{9}6s^{2}\). Losing two 6s and two 4f electrons gives \(\text{Tb}^{4+}\) with \(4f^{7}\), which is half-filled.
Yb is \([\text{Xe}]4f^{14}6s^{2}\). Losing two 6s electrons gives \(\text{Yb}^{2+}\) with \(4f^{14}\), which is completely filled.
Step 3: Compare the options
\(\text{Eu}^{2+}\) is \(4f^{7}\) but \(\text{Tm}^{2+}\) is \(4f^{13}\). \(\text{Sm}^{2+}\) is \(4f^{6}\) and \(\text{Dy}^{3+}\) is \(4f^{9}\). Only option (C) fits both conditions.
Final Answer:
The half-filled and completely filled ions are Tb4+ and Yb2+ respectively.
\[ \boxed{\text{(C) }\text{Tb}^{4+}\text{ and }\text{Yb}^{2+}} \]