Question:

Identify the isomerism exhibited by methoxyethane and propan-1-ol.

Show Hint

Alcohols and ethers with the same carbon count are classic textbook examples of functional group isomers. They always share the general formula $C_nH_{2n+2}O$.
Updated On: Jun 4, 2026
  • Position isomerism
  • Chain isomerism
  • Functional group isomerism
  • Metamerism
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Question:
We must determine the specific type of structural isomerism existing between methoxyethane and propan-1-ol.

Step 2: Detailed Explanation:
First, let's write out their molecular structures and formulas:

Methoxyethane: $CH_3-CH_2-O-CH_3$. It is an ether. Its molecular formula is $C_3H_8O$.

Propan-1-ol: $CH_3-CH_2-CH_2-OH$. It is an alcohol. Its molecular formula is $C_3H_8O$.
Both compounds possess the exact same molecular formula ($C_3H_8O$) but feature entirely different functional groups (an ether group versus a hydroxyl/alcohol group).
Isomers differing in their functional groups are called functional group isomers.

Step 3: Final Answer:
The isomerism exhibited is functional group isomerism, matching option (C).
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