Question

Identify the INCORRECT statement for isobaric process.

• A. \(\Delta p=0\)
• B. \(W\neq 0\)
• C. \(Q\neq 0\)
• D. \(\Delta U=0\)

Hint:

An isobaric process happens at constant pressure. Check each statement against what happens to volume, temperature and internal energy.

Answer 1

The Correct Option is D

Step 1: Understanding the Concept
In an isobaric process the pressure stays constant, so \(\Delta p=0\). The volume and temperature change.

Step 2: Check each statement
(A) \(\Delta p=0\) is true. (B) Work \(W=p\Delta V\neq0\) is true. (C) Heat \(Q=\Delta U+W\neq0\) is true.

Step 3: The incorrect one
The temperature changes, so the internal energy of the gas changes and \(\Delta U\neq0\). The statement \(\Delta U=0\) is valid only for an isothermal process of an ideal gas.

Final Answer:
The incorrect statement is that the change in internal energy is zero. \[ \boxed{\text{(D) }\Delta U=0} \]