Question:
Identify the hybridization in central metal of \([\text{Fe}(\text{CO})_5]\) complex.
Identify the hybridization in central metal of \([\text{Fe}(\text{CO})_5]\) complex.
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Fe in Fe(CO)$_5$ is $3d^8 4s^0$ after pairing electrons, giving $dsp^3$.
Updated On: Oct 1, 2026
- \(dsp^3\)
- \(sp^3d^2\)
- \(d^2sp^3\)
- \(sp^3\)
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The Correct Option is A
Solution and Explanation
Step 1: Configuration of Fe
Fe has \(3d^64s^2\). CO is a strong field ligand, so the electrons rearrange to \(3d^8\), with the \(4s^2\) electrons pushed into \(3d\).
Step 2: Hybrid orbitals
Five CO ligands need five empty orbitals: one \(3d\), one \(4s\) and three \(4p\). This is \(dsp^3\) hybridisation.
The shape is trigonal bipyramidal.
Step 3: Other options
\(sp^3d^2\) and \(d^2sp^3\) would give six ligands. \(sp^3\) would give four. Option (A).
Final Answer:
Fe in Fe(CO)\(_5\) is \(dsp^3\) hybridised, option (A). \[ \boxed{\text{(A) } dsp^3} \]
Fe has \(3d^64s^2\). CO is a strong field ligand, so the electrons rearrange to \(3d^8\), with the \(4s^2\) electrons pushed into \(3d\).
Step 2: Hybrid orbitals
Five CO ligands need five empty orbitals: one \(3d\), one \(4s\) and three \(4p\). This is \(dsp^3\) hybridisation.
The shape is trigonal bipyramidal.
Step 3: Other options
\(sp^3d^2\) and \(d^2sp^3\) would give six ligands. \(sp^3\) would give four. Option (A).
Final Answer:
Fe in Fe(CO)\(_5\) is \(dsp^3\) hybridised, option (A). \[ \boxed{\text{(A) } dsp^3} \]
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