Question:

Identify the geometry of \([\text{Ni(CN)}_{4}]^{2-}\) complex.

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Ni2+ is d8 and cyanide is a strong field ligand, which pairs the electrons and gives dsp2 hybridisation.
Updated On: Nov 12, 2026
  • Octahedral
  • Tetrahedral
  • Square planar
  • Hexagonal
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The Correct Option is C

Solution and Explanation

Step 1: Understanding the Concept
The geometry of a complex follows from the hybridisation of the central metal ion, which depends on the strength of the ligand.

Step 2: Find the metal configuration
In \([\text{Ni(CN)}_4]^{2-}\), Ni is in the +2 state: \(3d^{8}\).

Step 3: Effect of the ligand
\(\text{CN}^{-}\) is a strong field ligand, so the eight d electrons pair up in four d orbitals and one 3d orbital is vacated.

Step 4: Hybridisation
One 3d, the 4s and two 4p orbitals mix to give \(dsp^{2}\) hybrid orbitals, which are directed to the corners of a square.

Final Answer:
The complex is square planar. \[ \boxed{\text{(C) }\text{Square planar}} \]
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