Step 1: Understanding the Concept:
The extent of physical adsorption depends on how easily a gas can be liquefied. Easily liquefiable gases have stronger van der Waals forces and are adsorbed more.
Step 2: Link to critical temperature:
A higher critical temperature means the gas liquefies more easily. So the gas with the highest critical temperature is adsorbed most.
Step 3: Compare the gases:
Approximate critical temperatures: \(\text{H}_2\) 33 K, \(\text{N}_2\) 126 K, \(\text{O}_2\) 155 K, \(\text{SO}_2\) 431 K. \(\text{SO}_2\) is the highest.
Step 4: Why the other options are wrong.
\(\text{N}_2\), \(\text{O}_2\) and \(\text{H}_2\) are permanent gases with weak intermolecular forces and low critical temperatures, so they are adsorbed far less.
Final Answer:
Sulphur dioxide is adsorbed the most.
\[ \boxed{\text{(D) }\text{SO}_{2(g)}} \]