Question:

Identify the correct sequence of reactions and products for the following scheme.

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In reactions involving phenol and sodium hydroxide, typical reactions include the Kolbe reaction (formation of salicylic acid) and ether formation via methylation.
Updated On: Apr 28, 2026
  • \( P_1 = \text{Phenol}, P_2 = \text{Salicylaldehyde}, P_3 = \text{Cyclohexanol}, P_4 = \text{Phenylacetate} \)
  • \( P_1 = \text{Benzene}, P_2 = \text{Salicylic acid}, P_3 = \text{Cyclohexanol}, P_4 = \text{Phenylacetate} \)
  • \( P_1 = \text{Phenol}, P_2 = \text{Salicylic acid}, P_3 = \text{Anisole}, P_4 = \text{Aspirin} \)
  • \( P_1 = \text{Phenol}, P_2 = \text{Salicylic acid}, P_3 = \text{Anisole}, P_4 = \text{Phenylacetate} \)
  • \( P_1 = \text{Cyclohexanol}, P_2 = \text{Salicylic acid}, P_3 = \text{Phenol}, P_4 = \text{Aspirin} \)
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The Correct Option is C

Solution and Explanation

Step 1: Analyze the given reaction conditions.
- Reaction (i): Phenol reacts with sodium hydroxide and hydrogen ion to form phenoxide. This matches \( P_1 \) as Phenol.
- Reaction (ii): Phenol undergoes a Kolbe reaction with sodium hydroxide and carbon dioxide, resulting in the formation of salicylic acid. So, \( P_2 \) is Salicylic acid.
- Reaction (iii): The reaction with sodium hydroxide and methyl chloride suggests a methylation, leading to the formation of anisole (phenyl methyl ether). Therefore, \( P_3 \) is Anisole.
- Reaction (iv): Phenylacetate reacts with sodium hydroxide and carbon dioxide, which forms aspirin (acetylsalicylic acid). Hence, \( P_4 \) is Aspirin.

Step 2: Write the correct product names based on reactions.

Thus, the final products are: \[ P_1 = \text{Phenol}, P_2 = \text{Salicylic acid}, P_3 = \text{Anisole}, P_4 = \text{Aspirin} \]

Step 3: Final conclusion.

Therefore, the correct sequence is option (3): \[ \boxed{P_1 = \text{Phenol}, P_2 = \text{Salicylic acid}, P_3 = \text{Anisole}, P_4 = \text{Aspirin}} \] So, the correct answer is: \[ \boxed{(3)} \]
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