Question:
Identify the correct reagents that would bring about the following transformation.
Identify the correct reagents that would bring about the following transformation.
Updated On: Jan 13, 2026
- (i) H2O/H+
(ii) CrO3 - (i) BH3
(ii) \(H_2O_2/O^\ominus H\)
(iii) PCC - (i) BH3
(ii) \(H_2O_2/O^\ominus H\)
(iii) alk. KMnO4 - (iv)\(H_3O^\oplus\)
(i) H2O/H+
(ii) PCC
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Given Transformation
The transformation likely involves oxidation or hydroboration-oxidation, depending on the functional groups present.
Step 2: Analyze the Reagents
- \( BH_3 \) followed by \( H_2O_2/OH^- \): This is the hydroboration-oxidation reaction, which converts an alkene to an anti-Markovnikov alcohol.
- PCC (Pyridinium Chlorochromate): A mild oxidizing agent that converts primary alcohols to aldehydes and secondary alcohols to ketones.
- Chromic acid (\( CrO_3 \)) in acidic medium: A strong oxidizing agent that converts alcohols to carboxylic acids.
- Acidic water (\( H_2O/H^+ \)): Used for hydration of alkenes to form Markovnikov alcohols.
Step 3: Identify the Correct Set of Reagents
Since the transformation involves hydration followed by oxidation, the correct sequence of reagents is:
- \( BH_3 \) (Hydroboration step).
- \( H_2O_2/OH^- \) (Oxidation to form alcohol).
- \( PCC \) (Mild oxidation to aldehyde).
Step 4: Conclusion
The correct answer is:
Option (2): (i) \( BH_3 \), (ii) \( H_2O_2/OH^- \), (iii) PCC.
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