Question:

Identify the amine having highest $\text{p}\text{K}_{\text{b}}$ value.

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Basicity $\propto \frac{1}{pK_b}$. Aromatic amines (lone pair in resonance) are always weaker than aliphatic amines.
Updated On: Apr 26, 2026
  • $(\text{CH}_3)_3\text{N}$
  • $\text{C}_6\text{H}_5\text{CH}_2\text{NH}_2$
  • $\text{C}_6\text{H}_5\text{NH}_2$
  • $(\text{CH}_3)_2\text{NH}$
Show Solution
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The Correct Option is C

Solution and Explanation

Step 1: Concept
Highest $pK_b$ value = Weakest base.
Step 2: Basicity Trend
- Aliphatic amines are more basic than ammonia. - Aromatic amines (like Aniline, $C_6H_5NH_2$) are significantly weaker bases because the lone pair on Nitrogen is delocalized into the benzene ring. - (B) is Benzylamine, where the $-NH_2$ is not directly on the ring, so it is more basic than aniline.
Step 3: Conclusion
Aniline is the weakest base among the options, thus having the highest $pK_b$.
Final Answer: (C)
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