Question:
Identify product ' \(X\) ' obtained in the following reaction.
\[ \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Br}+\mathrm{CH}_3 \mathrm{COOAg} \xrightarrow{\Delta} \mathrm{X}+\mathrm{AgBr} \]
Identify product ' \(X\) ' obtained in the following reaction.
\[ \mathrm{CH}_3 \mathrm{CH}_2 \mathrm{Br}+\mathrm{CH}_3 \mathrm{COOAg} \xrightarrow{\Delta} \mathrm{X}+\mathrm{AgBr} \]
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An alkyl halide reacts with silver salt of a carboxylic acid to give an ester.
Updated On: Nov 13, 2026
\(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{COOCH}_{3}\)
\(\mathrm{CH}_{3}\mathrm{COOCH}_{2}\mathrm{CH}_{3}\)
\(\mathrm{CH}_{3}\mathrm{COOCH}_{3}\)
\(\mathrm{CH}_{3}\mathrm{CH}_{2}\mathrm{COOCH}_{2}\mathrm{CH}_{3}\)
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
Silver carboxylate attacks the alkyl halide: \(\text{RCOOAg}+\text{R}'\text{X}\rightarrow\text{RCOOR}'+\text{AgX}\).
Step 2: Apply
\(\text{CH}_3\text{COO}^{-}\) replaces \(\text{Br}^{-}\) on \(\text{CH}_3\text{CH}_2\text{Br}\).
Step 3: Product
\(\text{CH}_3\text{COOCH}_2\text{CH}_3\) (ethyl ethanoate). Option (B).
Final Answer:
The product X is ethyl ethanoate. \[ \boxed{\text{(B) }\mathrm{CH}_{3}\mathrm{COOCH}_{2}\mathrm{CH}_{3}} \]
Silver carboxylate attacks the alkyl halide: \(\text{RCOOAg}+\text{R}'\text{X}\rightarrow\text{RCOOR}'+\text{AgX}\).
Step 2: Apply
\(\text{CH}_3\text{COO}^{-}\) replaces \(\text{Br}^{-}\) on \(\text{CH}_3\text{CH}_2\text{Br}\).
Step 3: Product
\(\text{CH}_3\text{COOCH}_2\text{CH}_3\) (ethyl ethanoate). Option (B).
Final Answer:
The product X is ethyl ethanoate. \[ \boxed{\text{(B) }\mathrm{CH}_{3}\mathrm{COOCH}_{2}\mathrm{CH}_{3}} \]
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