Question:
Identify product 'B' in the following sequence of reactions.
\(\text{Aniline}\xrightarrow{\text{NaNO}_{2}+\text{HCl},\ 273\ \text{K}}A\xrightarrow{\text{H}_{2}\text{O},\ \Delta }B+\text{N}_{2}\uparrow\)
Identify product 'B' in the following sequence of reactions.
\(\text{Aniline}\xrightarrow{\text{NaNO}_{2}+\text{HCl},\ 273\ \text{K}}A\xrightarrow{\text{H}_{2}\text{O},\ \Delta }B+\text{N}_{2}\uparrow\)
\(\text{Aniline}\xrightarrow{\text{NaNO}_{2}+\text{HCl},\ 273\ \text{K}}A\xrightarrow{\text{H}_{2}\text{O},\ \Delta }B+\text{N}_{2}\uparrow\)
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Aniline gives a diazonium salt at 273 K, and warming that salt with water gives phenol.
Updated On: Nov 12, 2026
- Sodium phenoxide
- Phenol
- Benzenediazonium chloride
- Nitrobenzene
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The Correct Option is B
Solution and Explanation
Step 1: Understanding the Concept
Primary aromatic amines react with \(\text{NaNO}_2\) and HCl at 273 K to form diazonium salts (diazotisation).
Step 2: Step 1
\(\text{C}_6\text{H}_5\text{NH}_2+\text{NaNO}_2+2\text{HCl}\rightarrow\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^-+\text{NaCl}+2\text{H}_2\text{O}\)
So A is benzenediazonium chloride.
Step 3: Step 2
Warming the diazonium salt with water replaces the diazonium group by OH and nitrogen escapes.
\(\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^-+\text{H}_2\text{O}\rightarrow\text{C}_6\text{H}_5\text{OH}+\text{N}_2+\text{HCl}\)
So B is phenol.
Final Answer:
B is phenol. \[ \boxed{\text{(B) }\text{Phenol}} \]
Primary aromatic amines react with \(\text{NaNO}_2\) and HCl at 273 K to form diazonium salts (diazotisation).
Step 2: Step 1
\(\text{C}_6\text{H}_5\text{NH}_2+\text{NaNO}_2+2\text{HCl}\rightarrow\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^-+\text{NaCl}+2\text{H}_2\text{O}\)
So A is benzenediazonium chloride.
Step 3: Step 2
Warming the diazonium salt with water replaces the diazonium group by OH and nitrogen escapes.
\(\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^-+\text{H}_2\text{O}\rightarrow\text{C}_6\text{H}_5\text{OH}+\text{N}_2+\text{HCl}\)
So B is phenol.
Final Answer:
B is phenol. \[ \boxed{\text{(B) }\text{Phenol}} \]
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