Question:
Identify optically inactive compound from the following.
Identify optically inactive compound from the following.
Show Hint
A compound with no chiral carbon is optically inactive.
Updated On: Nov 12, 2026
- Lactic acid
- Glucose
- Isopropyl alcohol
- 2-chlorobutane
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept
A compound is optically active if it has a chiral carbon (four different groups) and no symmetry plane.
Step 2: Check the options
Lactic acid, glucose and 2-chlorobutane each have at least one chiral carbon.
Isopropyl alcohol, \(\text{CH}_3\text{CH(OH)CH}_3\), has a central carbon bonded to two identical methyl groups.
Step 3: Conclusion
Isopropyl alcohol has no chiral carbon, so it is optically inactive.
Final Answer:
Isopropyl alcohol is optically inactive. \[ \boxed{\text{(C) }\text{Isopropyl alcohol}} \]
A compound is optically active if it has a chiral carbon (four different groups) and no symmetry plane.
Step 2: Check the options
Lactic acid, glucose and 2-chlorobutane each have at least one chiral carbon.
Isopropyl alcohol, \(\text{CH}_3\text{CH(OH)CH}_3\), has a central carbon bonded to two identical methyl groups.
Step 3: Conclusion
Isopropyl alcohol has no chiral carbon, so it is optically inactive.
Final Answer:
Isopropyl alcohol is optically inactive. \[ \boxed{\text{(C) }\text{Isopropyl alcohol}} \]
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