Question:
Identify isoelectronic pair from following.
Identify isoelectronic pair from following.
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Total electrons = Atomic number - (Charge).
Updated On: Apr 26, 2026
- Ne and $\text{O}^{--}$
- $\text{Cl}^-$ and $\text{Ca}$
- $\text{Ar}$ and $\text{F}^-$
- $\text{K}^+$ and $\text{Al}^{+3}$
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The Correct Option is A
Solution and Explanation
Step 1: Concept
Isoelectronic species are atoms or ions that have the same number of electrons.
Step 2: Electron Count
- (A) $Ne = 10 e^-$; $O^{2-} = 8 + 2 = 10 e^-$. (Match) - (B) $Cl^- = 17 + 1 = 18 e^-$; $Ca = 20 e^-$. - (C) $Ar = 18 e^-$; $F^- = 9 + 1 = 10 e^-$. - (D) $K^+ = 19 - 1 = 18 e^-$; $Al^{3+} = 13 - 3 = 10 e^-$.
Step 3: Conclusion
Only Ne and $O^{2-}$ have the same number of electrons.
Final Answer: (A)
Isoelectronic species are atoms or ions that have the same number of electrons.
Step 2: Electron Count
- (A) $Ne = 10 e^-$; $O^{2-} = 8 + 2 = 10 e^-$. (Match) - (B) $Cl^- = 17 + 1 = 18 e^-$; $Ca = 20 e^-$. - (C) $Ar = 18 e^-$; $F^- = 9 + 1 = 10 e^-$. - (D) $K^+ = 19 - 1 = 18 e^-$; $Al^{3+} = 13 - 3 = 10 e^-$.
Step 3: Conclusion
Only Ne and $O^{2-}$ have the same number of electrons.
Final Answer: (A)
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