Question:

Identify homoleptic complex from following.

Show Hint

A homoleptic complex has only one kind of ligand bound to the metal.
Updated On: Nov 12, 2026
  • Bis(ethylenediamine)dithiocyanatoplatinum(IV)
  • Tetraamminecopper(II) ion
  • Triamminetrinitrocobalt(III)
  • Triamminetrithiocyanatorhodium(III)
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The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept
A homoleptic complex has the metal bound to only one kind of ligand. A heteroleptic complex has more than one kind.

Step 2: Check each option
Bis(ethylenediamine)dithiocyanatoplatinum(IV) has en and SCN, so it is heteroleptic.
Triamminetrinitrocobalt(III) has \(\text{NH}_3\) and \(\text{NO}_2\), and triamminetrithiocyanatorhodium(III) has \(\text{NH}_3\) and SCN, so both are heteroleptic.

Step 3: Conclusion
Tetraamminecopper(II), \([\text{Cu}(\text{NH}_3)_4]^{2+}\), has only ammine ligands, so it is homoleptic.

Final Answer:
The homoleptic complex is the tetraamminecopper(II) ion. \[ \boxed{\text{(B) }\text{Tetraamminecopper(II) ion}} \]
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