Question:
Identify glycosidic linkage present in maltose.
Identify glycosidic linkage present in maltose.
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Maltose has two alpha-D-glucose units joined through C-1 and C-4.
Updated On: Nov 12, 2026
- \(\alpha \text{-1, 2}\)
- \(\beta \text{-2, 1}\)
- \(\beta \text{-1, 3}\)
- \(\alpha \text{-1,4}\)
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The Correct Option is D
Solution and Explanation
Step 1: Understanding the Concept
Maltose is a disaccharide made from two glucose units joined by a glycosidic bond.
Step 2: Structure
C-1 of the first glucose, in the \(\alpha\) form, is linked through oxygen to C-4 of the second glucose.
C-1 of the second unit stays free, so maltose is a reducing sugar.
Step 3: Conclusion
The linkage in maltose is \(\alpha\)-1,4.
Final Answer:
Maltose has an \(\alpha\)-1,4 glycosidic linkage. \[ \boxed{\text{(D) }\alpha \text{-1,4}} \]
Maltose is a disaccharide made from two glucose units joined by a glycosidic bond.
Step 2: Structure
C-1 of the first glucose, in the \(\alpha\) form, is linked through oxygen to C-4 of the second glucose.
C-1 of the second unit stays free, so maltose is a reducing sugar.
Step 3: Conclusion
The linkage in maltose is \(\alpha\)-1,4.
Final Answer:
Maltose has an \(\alpha\)-1,4 glycosidic linkage. \[ \boxed{\text{(D) }\alpha \text{-1,4}} \]
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