Question:
Identify cationic complex from following.
Identify cationic complex from following.
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When the name ends with a cation (like platinum(IV) complex) and has halide counter ions outside the bracket, it is a cationic complex.
Updated On: Jun 4, 2026
- Na\(_3\)[AlF\(_6\)]
- [Pt(NH\(_3\))\(_2\)Cl\(_2\)]
- K\(_4\)[Fe(CN)\(_6\)]
- [PtBr\(_2\)(NH\(_3\))\(_4\)]Br\(_2\)
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Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Step 1: Understanding the Question:
A cationic complex is one where the complex ion carries a positive charge. We must examine each option to find which contains a complex cation.
Step 2: Key Formula or Approach:
Break each compound into its ionic components. The species inside the coordination sphere is the complex ion. Its charge is determined by the overall compound charge and counter ions.
Step 3: Detailed Explanation:
- (A) Na\(_3\)[AlF\(_6\)] → 3Na\(^+\) and [AlF\(_6\)]\(^{3-}\) (anionic complex). - (B) [Pt(NH\(_3\))\(_2\)Cl\(_2\)] → neutral complex, no counter ions. - (C) K\(_4\)[Fe(CN)\(_6\)] → 4K\(^+\) and [Fe(CN)\(_6\)]\(^{4-}\) (anionic complex). - (D) [PtBr\(_2\)(NH\(_3\))\(_4\)]Br\(_2\) → dissociates into [PtBr\(_2\)(NH\(_3\))\(_4\)]\(^{2+}\) and 2Br\(^-\); the complex ion is cationic.
Step 4: Final Answer:
The cationic complex is option (D).
A cationic complex is one where the complex ion carries a positive charge. We must examine each option to find which contains a complex cation.
Step 2: Key Formula or Approach:
Break each compound into its ionic components. The species inside the coordination sphere is the complex ion. Its charge is determined by the overall compound charge and counter ions.
Step 3: Detailed Explanation:
- (A) Na\(_3\)[AlF\(_6\)] → 3Na\(^+\) and [AlF\(_6\)]\(^{3-}\) (anionic complex). - (B) [Pt(NH\(_3\))\(_2\)Cl\(_2\)] → neutral complex, no counter ions. - (C) K\(_4\)[Fe(CN)\(_6\)] → 4K\(^+\) and [Fe(CN)\(_6\)]\(^{4-}\) (anionic complex). - (D) [PtBr\(_2\)(NH\(_3\))\(_4\)]Br\(_2\) → dissociates into [PtBr\(_2\)(NH\(_3\))\(_4\)]\(^{2+}\) and 2Br\(^-\); the complex ion is cationic.
Step 4: Final Answer:
The cationic complex is option (D).
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