Question:
I\(_2\) dissolves in KI solution due to formation of
I\(_2\) dissolves in KI solution due to formation of
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I\(_3^-\) is linear and has a bond order of 1.5.
Updated On: Apr 20, 2026
- \(\mathrm{KI}_2\) and \(\mathrm{I}^-\)
- \(\mathrm{K}^+, \mathrm{I}^-, \mathrm{I}_2\)
- \(\mathrm{I}_3^-\)
- None of the above
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Concept:
Iodine is soluble in KI solution due to complex formation.
Step 2: Detailed Explanation:
I\(_2\) reacts with I\(^-\) from KI to form the triiodide ion: I\(_2\) + I\(^-\) → I\(_3^-\). This complex is soluble in water.
Step 3: Final Answer:
\(\mathrm{I}_3^-\)
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