Question

Hydroboration-oxidation of but-1-ene forms

• A. Butanal
• B. Butanone
• C. Butan-1-ol
• D. Butan-2-ol

Hint:

Hydroboration-oxidation gives anti-Markovnikov alcohol. For terminal alkene, the product is usually a primary alcohol.

Answer 1

The Correct Option is C

Concept:
Hydroboration-oxidation adds water across a double bond in anti-Markovnikov manner. Thus, in terminal alkenes, the \(-\text{OH}\) group goes to the terminal carbon atom. ip

Step 1: Write the starting alkene.
But-1-ene is: \[ \text{CH}_2=\text{CH}-\text{CH}_2-\text{CH}_3 \] ip

Step 2: Apply hydroboration-oxidation rule.
Hydroboration-oxidation places the hydroxyl group on the less substituted carbon. Therefore, \(-\text{OH}\) attaches to carbon-1. ip

Step 3: Write the product.
The product formed is: \[ \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2\text{OH} \] which is butan-1-ol. ip Hence, the correct answer is:
\[ \boxed{(C)\ \text{Butan-1-ol}} \]